LeakLWE2/framework/geometry.sage

from numpy.linalg import inv as np_inv
# from numpy.linalg import slogdet as np_slogdet
from numpy import array
import numpy as np


def dual_basis(B):
    """
    Compute the dual basis of B
    """
    return B.pseudoinverse().transpose()


def projection_matrix(A):
    """
    Construct the projection matrix orthogonally to Span(V)
    """
    S = A * A.T
    return A.T * S.inverse() * A


def project_against(v, X):
    """ Project matrix X orthonally to vector v"""
    # Pv = projection_matrix(v)
    # return X - X * Pv
    Z = (X * v.T) * v / scal(v * v.T)
    return X - Z


# def make_primitive(B, v):
#     assert False
#     # project and Scale v's in V so that each v
#     # is in the lattice, and primitive in it.
#     # Note: does not make V primitive as as set of vector !
#     # (e.g. linear dep. not eliminated)
#     PB = projection_matrix(B)
#     DT = dual_basis(B).T
#     v = vec(v) * PB
#     w = v * DT
#     den = lcm([x.denominator() for x in w[0]])
#     num = gcd([x for x in w[0] * den])
#     if num==0:
#         return None
#     v *= den/num
#     return v


def vol(B):
    return sqrt(det(B * B.T))


def project_and_eliminate_dep(B, W):
    # Project v on Span(B)
    PB = projection_matrix(B)
    V = W * PB
    rank_loss = V.nrows() - V.rank()

    if rank_loss > 0:
        print("WARNING: their were %d linear dependencies out of %d " %
              (rank_loss, V.nrows()))
        V = V.LLL()
        V = V[rank_loss:]

    return V


def is_cannonical_direction(v):
    v = vec(v)
    return sum([x != 0 for x in v[0]]) == 1


def cannonical_param(v):
    v = vec(v)
    assert is_cannonical_direction(v)
    i = [x != 0 for x in v[0]].index(True)
    return i, v[0, i]

def xgcd_of_list(a):
    (g, s, t) = xgcd(a[0], a[1])
    bezouts = [s, t]

    for v in a[2:]:
        (g, s_, t_) = xgcd(g, v)
        bezouts = [b*s_ for b in bezouts]
        bezouts.append(t_)

    return (g, bezouts)

def remove_linear_dependencies(B, dim=None):
    nrows = B.nrows()
    if dim is None or nrows > dim:
        # Determine the number of dependencies
        K, r = None, None
        if dim is None:
            K = B.left_kernel().basis_matrix() # I assume that the cost of "left_kernel" is negligeable before "LLL"
            r = K.dimensions()[0]
        else:
            r = nrows-dim
<<<<<<< HEAD

        if r == 1 and False:
            print("Use Better Algo")
=======
        
        if r == 1 and False:
>>>>>>> 81324f49c90b518d464e18b0204408a3aa6b5eff
            # Find a linear dependency
            if K is None:
                K = B.left_kernel().basis_matrix()
            assert K.dimensions()[0] == 1
            combinaison = K[0]
            combinaison *= lcm([v.denominator() for v in combinaison])
            print(combinaison)

            pivot, pivot_value = None, None
            for ind, value in enumerate(combinaison):
                if abs(value) == 1:
                    pivot, pivot_value = ind, value
                    break

            if pivot_value is None:
                print('Complex case')
                for ind, value in enumerate(combinaison):
                    if abs(value) > 0 and gcd([v for i,v in enumerate(combinaison) if i!=ind]) == 1:
                        if pivot is None or abs(value)<abs(pivot_value):
                            pivot, pivot_value = ind, value

                if pivot_value < 0:
                    combinaison = vector(ZZ, [-v for v in combinaison])

                _, bezouts = xgcd_of_list([v for i,v in enumerate(combinaison) if i!=pivot])

                factor = combinaison[pivot]-1
                for i in range(len(combinaison)):
                    ind = i if i < pivot else i-1
                    if i != pivot:
                        B[i] += factor*bezouts[ind]*B[pivot]
                combinaison[pivot] += -factor
                assert (combinaison*B).is_zero(), 'It is not a linear dependency anymore !'

            assert abs(combinaison[pivot]) == 1, f'Error abs(combinaison[pivot]) == {abs(combinaison[pivot])} != 1'
            B = B[[i for i in range(B.dimensions()[0]) if i != pivot]]

        else:
            B = B.LLL()
            B = B[r:]
    return B

def lattice_orthogonal_section(D, V, maintains_basis=True):
    """
    Compute the intersection of the lattice L(B)
    with the hyperplane orthogonal to Span(V).
    (V can be either a vector or a matrix)
    INPUT AND OUTPUT DUAL BASIS
    Algorithm:
    - project V onto Span(B)
    - project the dual basis onto orth(V)
    - eliminate linear dependencies (LLL)
    - go back to the primal.
    """

    #V = project_and_eliminate_dep(D, V) ## No need because D is full-rank
    #r = V.nrows()

    # Project the dual basis orthogonally to v
    PV = projection_matrix(V)
    D = D - D * PV

    # Eliminate linear dependencies
    if maintains_basis:
        D = remove_linear_dependencies(D)

    # Go back to the primal
    return D


def lattice_project_against(B, V, maintains_basis=True):
    """
    Compute the projection of the lattice L(B) orthogonally to Span(V). All vectors if V
    (or at least their projection on Span(B)) must belong to L(B).
    Algorithm:
    - project V onto Span(B)
    - project the basis onto orth(V)
    - eliminate linear dependencies (LLL)
    """
    # Project v on Span(B)
    #V = project_and_eliminate_dep(B, V) ## No need because D is full-rank
    #r = V.nrows() # Useless

    # Check that V belogs to L(B)
    D = dual_basis(B)
    M = D * V.T
    if not lcm([x.denominator() for x in M.list()]) == 1:
        raise ValueError("Not in the lattice")

    # Project the basis orthogonally to v
    PV = projection_matrix(V)
    B = B - B * PV

    # Eliminate linear dependencies
    if maintains_basis:
        B = remove_linear_dependencies(B)

    # Go back to the primal
    return B


def lattice_modular_intersection(D, V, k, maintains_basis=True):
    """
    Compute the intersection of the lattice L(B) with
    the lattice {x | x*V = 0 mod k}
    (V can be either a vector or a matrix)
    Algorithm:
    - project V onto Span(B)
    - append the equations in the dual
    - eliminate linear dependencies (LLL)
    - go back to the primal.
    """
    # Project v on Span(B)
    #V = project_and_eliminate_dep(D, V) ## No need because D is full-rank
    #r = V.nrows() # Useless

    # append the equation in the dual
    V /= k
    D = D.stack(V)

    # Eliminate linear dependencies
    if maintains_basis:
        D = remove_linear_dependencies(D)

    # Go back to the primal
    return D


def is_diagonal(M):
    if M.nrows() != M.ncols():
        return False
    A = M.numpy()
    return np.all(A == np.diag(np.diagonal(A)))


def logdet(M, exact=False):
    """
    Compute the log of the determinant of a large rational matrix,
    tryping to avoid overflows.
    """
    if not exact:
        MM = array(M, dtype=float)
        _, l = slogdet(MM)
        return l

    a = abs(M.det())
    l = 0

    while a > 2**32:
        l += RR(32 * ln(2))
        a /= 2**32

    l += ln(RR(a))
    return l


def degen_inverse(S, B=None):
    """ Compute the inverse of a symmetric matrix restricted
    to its span
    """
    # Get an orthogonal basis for the Span of B

    if B is None:
        # Get an orthogonal basis for the Span of B
        V = S.echelon_form()
        V = V[:V.rank()]
        P = projection_matrix(V)
    else:
        P = projection_matrix(B)

    # make S non-degenerated by adding the complement of span(B)
    C = identity_matrix(S.ncols()) - P
    Sinv = (S + C).inverse() - C

    assert S * Sinv == P, "Consistency failed (probably not your fault)."
    assert P * Sinv == Sinv, "Consistency failed (probably not your fault)."

    return Sinv


def degen_logdet(S, B=None):
    """ Compute the determinant of a symmetric matrix
    sigma (m x m) restricted to the span of the full-rank
    rectangular (k x m, k <= m) matrix V
    """
    # Get an orthogonal basis for the Span of B

    if B is None:
        # Get an orthogonal basis for the Span of B
        V = S.echelon_form()
        V = V[:V.rank()]
        P = projection_matrix(V)
    else:
        P = projection_matrix(B)

    # Check that S is indeed supported by span(B)
    #assert S == P.T * S * P
    assert (S - P.T * S * P).norm() <= 1e-10

    # make S non-degenerated by adding the complement of span(B)
    C = identity_matrix(S.ncols()) - P
    l3 = logdet(S + C)
    return l3


def square_root_inverse_degen(S, B=None):
    """ Compute the determinant of a symmetric matrix
    sigma (m x m) restricted to the span of the full-rank
    rectangular (k x m, k <= m) matrix V
    """
    if B is None:
        # Get an orthogonal basis for the Span of B
        V = S.echelon_form()
        V = V[:V.rank()]
        P = projection_matrix(V)
    else:
        P = projection_matrix(B)

    # make S non-degenerated by adding the complement of span(B)
    C = identity_matrix(S.ncols()) - P
    S_inv = np_inv(array((S + C), dtype=float))
    S_inv = array(S_inv, dtype=float)
    L_inv = cholesky(S_inv)
    L_inv = round_matrix_to_rational(L_inv)
    L = L_inv.inverse()

    return L, L_inv


def build_standard_substitution_matrix(V, pivot=None, data=None, output_data=False):
    _, pivot = V.nonzero_positions()[0] if (pivot is None) else (None, pivot)
    assert V[0,pivot] != 0, 'The value of the pivot must be non-zero.'
    dim = V.ncols()

    V1 = - V[0,:pivot] / V[0,pivot]
    V2 = - V[0,pivot+1:] / V[0,pivot]

    Gamma = zero_matrix(QQ, dim,dim-1)
    Gamma[:pivot,:pivot] = identity_matrix(pivot)
    Gamma[pivot,:pivot] = V1
    Gamma[pivot,pivot:] = V2
    Gamma[pivot+1:,pivot:] = identity_matrix(dim-pivot-1)

    data = data if not output_data else {}
    if data is not None:
        norm2 = 1 + scal(V1*V1.T) + scal(V2*V2.T)
        normalization_matrix = zero_matrix(QQ, dim-1,dim-1)
        normalization_matrix[:pivot,:pivot] = identity_matrix(pivot) - V1.T*V1 / norm2
        normalization_matrix[pivot:,pivot:] = identity_matrix(dim-pivot-1) - V2.T*V2 / norm2
        normalization_matrix[:pivot,pivot:] = - V1.T*V2 / norm2
        normalization_matrix[pivot:,:pivot] = - V2.T*V1 / norm2

        data['det'] = norm2
        data['normalization_matrix'] = normalization_matrix

    if output_data:
        return Gamma, data
    else:
        return Gamma